Hello, vk_Notepad_123,
If I, fully, understand you :
For each block of two lines, below, with an identical IP address nnn.nnn.nnn.nnn
Random text1 nnn.nnn.nnn.nnn Random text2
Random text3 nnn.nnn.nnn.nnn Random text4
You would like to obtain, after replacement, the text below :
Random text1 nnn.nnn.nnn.nnn Random text2
Random text4
abcd-efg-ijk
If so, use the following S/R, in regular expression search mode :
SEARCH ^.*((?:\d{1,3}\.){3}\d{1,3}).*\R\K.*\1\h*(.+)
REPLACE \2\r\nabcd-efg-ijk
IMPORTANT : Due to the \K form, you must click, exclusively, on the Replace All button ( DON’T use the step-by-step replacement, with the Replace button )
NOTES :
This regex will work even if Random text1 and/or Random text2 and/or Random text3 does not exist
This regex will work even if no blank character ( space or tabulation ), exists between the IP address and Random text4, in second line
The part ((?:\d{1,3}\.){3}\d{1,3}) looks for four integers, from 1 to 3 digits, separated by the dot symbol. However, consider that this regex does not verify the integrity of the IP address. Indeed, this syntax would match the string 999.999.999.999, which is not, obviously, a valid IP address !
The IP address, preceded and followed by any range, even null, of characters ( .* ) and ended by its EOL characters ( \R ) is, then, forgotten by the regex engine, due to the \K syntax
Now, it tries to match the second line : any range even null, of characters, followed by the SAME IP address, stored as group 1 ( \1 ), followed by possible horizontal blank characters ( \h* )
As the previous syntax (?:\d{1,3}\.){3} defines a non-capturing group, repeated 3 times, the remainder of line 2, Random text4 (.+) ) is, therefore, stored as group2
In the replacement part, this second line is re-written with Random text4 ( \2 ), only, followed by a line break ( \r\n ), and, finally, followed by the simple string abcd-efg-ijk
Best Regards,
guy038
